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Class 10 Physics Current Electricity


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13.19Awaterheaterthatwllldeliver1 kgofwaterperminuteisrequired.Thewaterissuppliedat20∘Candanoutputtemperatureof80∘Cisdesired.Whatshouldbetheresistanceoftheheatingelementinthewaterifthelinevoltageis220 V?13.19 A water heater that wlll deliver 1 \mathrm{~kg} of water per minute is required. The water is supplied at 20^{\circ} \mathrm{C} and an output temperature of 80^{\circ} \mathrm{C} is desired. What should be the resistance of the heating element in the water if the line voltage is 220 \mathrm{~V} ?
Example: 13.6 What would be the resistance of the above bar at 500^{\circ} \mathrm{C} ?
Example: 13.6 What would be the resistance of the above bar at 500^{\circ} \mathrm{C} ?

Example:13.6Whatwouldbetheresistanceoftheabovebarat500∘C?Example: 13.6 What would be the resistance of the above bar at 500^{\circ} \mathrm{C} ?

13.7 Describe a circuit which will give a continuously var ying potential.
13.7 Describe a circuit which will give a continuously var ying potential.

13.7Describeacircuitwhichwillgiveacontinuouslyvaryingpotential. 13.7 Describe a circuit which will give a continuously var ying potential.

14.11. A resistor of resistance 5.6 \Omega is connected across a battery of 3.0 \mathrm{~V} by means of a wire of negligible resistance. A current of 0.5 A passes through the resistor.Calculate(a) Power dissipated in the resistor.(b) Total power produced by the battery.(c) Give the reason of difference between these two quantities.Ans. [(a) 1.4W(b) 1.5 \mathrm{~W} (c) some power is lost by the internal resistance of the battery]
14.11. A resistor of resistance 5.6 \Omega is connected across a battery of 3.0 \mathrm{~V} by means of a wire of negligible resistance. A current of 0.5 A passes through the resistor.Calculate(a) Power dissipated in the resistor.(b) Total power produced by the battery.(c) Give the reason of difference between these two quantities.Ans. [(a) 1.4W(b) 1.5 \mathrm{~W} (c) some power is lost by the internal resistance of the battery]

14.11.Aresistorofresistance5.6Ωisconnectedacrossabatteryof3.0 Vbymeansofawireofnegligibleresistance.Acurrentof0.5Apassesthroughtheresistor.Calculate(a)Powerdissipatedintheresistor.(b)Totalpowerproducedbythebattery.(c)Givethereasonofdifferencebetweenthesetwoquantities.Ans.[(a)1.4W(b)1.5 W(c)somepowerislostbytheinternalresistanceofthebattery]14.11. A resistor of resistance 5.6 \Omega is connected across a battery of 3.0 \mathrm{~V} by means of a wire of negligible resistance. A current of 0.5 A passes through the resistor.Calculate(a) Power dissipated in the resistor.(b) Total power produced by the battery.(c) Give the reason of difference between these two quantities.Ans. [(a) 1.4W(b) 1.5 \mathrm{~W} (c) some power is lost by the internal resistance of the battery]

13.10 Ten resistances of different value are connected in parallel. If the p.d.across one of them is 5 \mathrm{~V} . what is the p.d. across the remalning nine resistors?
13.10 Ten resistances of different value are connected in parallel. If the p.d.across one of them is 5 \mathrm{~V} . what is the p.d. across the remalning nine resistors?

13.10Tenresistancesofdifferentvalueareconnectedinparallel.Ifthep.d.acrossoneofthemis5 V.whatisthep.d.acrosstheremalningnineresistors?13.10 Ten resistances of different value are connected in parallel. If the p.d.across one of them is 5 \mathrm{~V} . what is the p.d. across the remalning nine resistors?

14.4. By applying a potential difference of 10 \mathrm{~V} across a conductor a current of 1.5 A passes through it. How much energy would be obtained from the current in 2 minutes?Ans. (1800 J)
14.4. By applying a potential difference of 10 \mathrm{~V} across a conductor a current of 1.5 A passes through it. How much energy would be obtained from the current in 2 minutes?Ans. (1800 J)

14.4.Byapplyingapotentialdifferenceof10 Vacrossaconductoracurrentof1.5Apassesthroughit.Howmuchenergywouldbeobtainedfromthecurrentin2minutes?Ans.(1800J)14.4. By applying a potential difference of 10 \mathrm{~V} across a conductor a current of 1.5 A passes through it. How much energy would be obtained from the current in 2 minutes?Ans. (1800 J)

13.6 When a metal object is heated. both its dimensions and fts resistlvity increase. Is the increase in resistivity likely to be a consequence of the increase in length?
13.6 When a metal object is heated. both its dimensions and fts resistlvity increase. Is the increase in resistivity likely to be a consequence of the increase in length?

13.6Whenametalobjectisheated.bothitsdimensionsandftsresistlvityincrease.Istheincreaseinresistivitylikelytobeaconsequenceoftheincreaseinlength?13.6 When a metal object is heated. both its dimensions and fts resistlvity increase. Is the increase in resistivity likely to be a consequence of the increase in length?

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