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##### Q.19 Graphite and diamond are two forms of carbon. The enthalpy of combustion of graphite at 25^{\circ} \mathrm{C} is -393.51 \mathrm{~kJ} mol-1 and that of diamond is -395.41 \mathrm{~kJ} \mathrm{~mol}^{-1} . What is the enthalpy change of the process? Graphite \rightarrow Diamond at the same temperature? \mathrm{C}_{2} \mathrm{H}_{4}(\mathrm{~g})+\mathrm{H}_{2}(\mathrm{~g}) \rightarrow \mathrm{C}_{2} \mathrm{H}_{6}(\mathrm{~g}) (Ans: 1.91 \mathrm{~kJ} \mathrm{~mol}^{-1} )

Q.5(a) Differentiate between the following:(i) Internal energy and enthalpy

Q.4. Define the following terms and give three examples of each(v) Exothermic reaction

Q.4. Define the following terms and give three examples of each(viii) Enthalpy of the system

(b) How do you measure the heat of combustion of a substance by bomb calorimeter.

Q.4. Define the following terms and give three examples of each(ii) Surroundings

Q.20 What is the meaning of the term enthalpy of ionization? If the heat of neutralization of \mathrm{HCl} and \mathrm{NaOH} is -57.3 \mathrm{~kJ} \mathrm{~mol}^{-1} and heat of neutralization of \mathrm{CH}_{3} \mathrm{COOH} with \mathrm{NaOH} is -55.2 \mathrm{~kJ} \mathrm{~mol}^{-1} calculate the enthalpy of ionization of \mathrm{CH}_{3} \mathrm{COOH} .(Ans: 2.1 \mathrm{~kJ} \mathrm{~mol}^{-1} )