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##### 14. Show that the area of a sector of a circular region of radius r is \frac{1}{2} r^{2} \theta where \theta is the circular measure of the central angle of the sector.

Q.43 1-\sec ^{2} \theta= is equal to(a) \tan ^{2} \theta (b) -\tan ^{2} \theta (c) \tan ^{2} \theta-1 (d) 1-\tan ^{2} \theta

1. Verify the following:(iii) 2 \sin 45^{\circ}+\frac{1}{2} \operatorname{cosec} 45^{\circ}=\frac{3}{\sqrt{2}}

2. Evaluate the following:ii) \frac{1-\tan ^{2} \frac{\pi}{3}}{1+\tan ^{2} \frac{\pi}{3}}