Theorem 9.1.2: If two angles of a triangle are congruent, then the sides opposite to them are also congruent.
Proof:
Given: In △ABC\triangle ABC△ABC We have, ∠B≅∠C\angle B \cong \angle C∠B≅∠C
To prove:
AB‾≅AC‾\overline{AB}\cong\overline{AC}AB≅AC
Construction: Draw a line AD‾\overline{AD}AD the bisector of ∠A\angle A∠A, meeting BC‾\overline{BC}BC at point DDD.