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Gravitation

Mass of Earth

Physics

STATEMENT:

Consider a body of mass mm is placed at the surface of the Earth. Let,

MEM_E = mass of earth.

RER_E = radius of earth, Which also is distance between the center of earth and the body.

GG = Universal gravitational constant.

DERIVATION:

By the Newton’s law of universal gravitation, the force between the body and the earth is given by:

F=GmMERE2\boxed{F =G\frac{mM_E}{{R_E}^2}} ……….. (i)

But the force with which the earth attracts a body towards its center is called weight of the body, i.e.

F=W=mgF = W=mg …………….. (ii)

Comparing equation (i) and (ii):

mg=GmMERE2mg =G\frac{mM_E}{{R_E}^2}

g=GMERE2g =G\frac{M_E}{{R_E}^2}

By re-arranging we get:

ME=gRE2G\boxed{M_E =g\frac{{R_E}^2}{G}}

Here,

g=9.8m/s2g = 9.8 \thinspace m/s² G=6.67x1011Nm2/kg2G = 6.67 \thinspace \text{x} \thinspace 10^{-11} \thinspace Nm^2/kg^2

RE=6.38x106mR_E = 6.38 \thinspace \text{x} \thinspace10^6\thinspace m

By substituting these values, we get:

ME=(9.8)(6.38x106)26.67x1011M_E =(9.8) \Large \frac{(6.38 \thinspace \text{x} \thinspace10^6)^2}{6.67 \thinspace \text{x} \thinspace 10^{-11}}

ME=6.0x1024kg\boxed{M_E = 6.0 \thinspace \text{x} \thinspace 10^{24} \thinspace kg}